this is short info of netCDF
-1 : Institut Source Ttype Levels Num Gridsize Num Dtype : Parameter name
1 : unknown unknown instant 1 1 4080 1 F32 : precip
Grid coordinates :
1 : lonlat > size : dim = 4080 nx = 68 ny = 60
x : first = 353.559998 last = 368.299988 inc = 0.219999854 degrees_east
y : first = 5.04000044 last = -7.93999958 inc = -0.220000267 degrees_north
and this is the ncdump -h of the netcdf:
dimensions:
x = 84 ;
y = 76 ;
ht = 1 ;
t = UNLIMITED ; // (93 currently)
variables:
float x(x) ;
x:standard_name = "longitude" ;
x:long_name = "longitude" ;
x:units = "degrees_east" ;
x:axis = "X" ;
float y(y) ;
y:standard_name = "latitude" ;
y:long_name = "latitude" ;
y:units = "degrees_north" ;
y:axis = "Y" ;
float ht(ht) ;
ht:units = "m" ;
ht:positive = "up" ;
ht:axis = "Z" ;
double t(t) ;
t:standard_name = "time" ;
t:units = "days since 1859-12-01 00:00:00" ;
t:calendar = "360_day" ;
float temp(t, ht, y, x) ;
temp:long_name = "TEMPERATURE AT 1.5M" ;
temp:units = "K" ;
temp:_FillValue = 2.e+20f ;
temp:missing_value = 2.e+20f ;
temp:source = "Unified Model Output:" ;
temp:name = "temp" ;
temp:title = "TEMPERATURE AT 1.5M" ;
temp:date = "01/12/59" ;
temp:time = "00:00" ;
temp:north_pole = 95.5f, 57.76f ;
// global attributes:
:CDI = "Climate Data Interface version 1.6.2 (
http://code.zmaw.de/projects/cdi)" ;
:Conventions = "CF-1.4" ;
:history = "Sun Oct 19 17:19:42 2014: cdo addc,-273.15 jja_temp_75_05.nc jja_tempc_75_05.nc\n",
"Sun Oct 19 16:58:39 2014: cdo selmon,6,7,8, tmp_mon_1975-2005.NC jja_temp_75_05.nc\n",
"Sun Oct 19 16:56:42 2014: cdo selyear,1975/2005 tmonthly tmp_mon_1975-2005.NC\n",
"Sun Sep 7 10:51:41 CDT 2014 - XCONV V1.91 16-February-2006" ;
:CDO = "Climate Data Operators version 1.6.2 (
http://code.zmaw.de/projects/cdo)" ;
}
Using matlab the plotting came out inseficient way. Simon and Dave looked in to it advised to post it. basd on that my quastion is, If rotated pole requires any conversion to regular lon lat or if any problem in the information that is provided, any advise is appreciated .